(x^2+3x-40)+(x^2-3x-28)=

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Solution for (x^2+3x-40)+(x^2-3x-28)= equation:


Simplifying
(x2 + 3x + -40) + (x2 + -3x + -28) = 0

Reorder the terms:
(-40 + 3x + x2) + (x2 + -3x + -28) = 0

Remove parenthesis around (-40 + 3x + x2)
-40 + 3x + x2 + (x2 + -3x + -28) = 0

Reorder the terms:
-40 + 3x + x2 + (-28 + -3x + x2) = 0

Remove parenthesis around (-28 + -3x + x2)
-40 + 3x + x2 + -28 + -3x + x2 = 0

Reorder the terms:
-40 + -28 + 3x + -3x + x2 + x2 = 0

Combine like terms: -40 + -28 = -68
-68 + 3x + -3x + x2 + x2 = 0

Combine like terms: 3x + -3x = 0
-68 + 0 + x2 + x2 = 0
-68 + x2 + x2 = 0

Combine like terms: x2 + x2 = 2x2
-68 + 2x2 = 0

Solving
-68 + 2x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '68' to each side of the equation.
-68 + 68 + 2x2 = 0 + 68

Combine like terms: -68 + 68 = 0
0 + 2x2 = 0 + 68
2x2 = 0 + 68

Combine like terms: 0 + 68 = 68
2x2 = 68

Divide each side by '2'.
x2 = 34

Simplifying
x2 = 34

Take the square root of each side:
x = {-5.830951895, 5.830951895}

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